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11x^2+9x-23=0
a = 11; b = 9; c = -23;
Δ = b2-4ac
Δ = 92-4·11·(-23)
Δ = 1093
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{1093}}{2*11}=\frac{-9-\sqrt{1093}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{1093}}{2*11}=\frac{-9+\sqrt{1093}}{22} $
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